(y^3-3y^2)(y^2-9)=0

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Solution for (y^3-3y^2)(y^2-9)=0 equation: 


Simplifying
(y3 + -3y2)(y2 + -9) = 0

Reorder the terms:
(-3y2 + y3)(y2 + -9) = 0

Reorder the terms:
(-3y2 + y3)(-9 + y2) = 0

Multiply (-3y2 + y3) * (-9 + y2)
(-3y2 * (-9 + y2) + y3(-9 + y2)) = 0
((-9 * -3y2 + y2 * -3y2) + y3(-9 + y2)) = 0
((27y2 + -3y4) + y3(-9 + y2)) = 0
(27y2 + -3y4 + (-9 * y3 + y2 * y3)) = 0
(27y2 + -3y4 + (-9y3 + y5)) = 0

Reorder the terms:
(27y2 + -9y3 + -3y4 + y5) = 0
(27y2 + -9y3 + -3y4 + y5) = 0

Solving
27y2 + -9y3 + -3y4 + y5 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), 'y2'.
y2(27 + -9y + -3y2 + y3) = 0


Subproblem 1
Set the factor 'y2' equal to zero and attempt to solve:

Simplifying
y2 = 0

Solving
y2 = 0

Move all terms containing y to the left, all other terms to the right.

Simplifying
y2 = 0

Take the square root of each side:
y = {0}

Subproblem 2
Set the factor '(27 + -9y + -3y2 + y3)' equal to zero and attempt to solve:

Simplifying
27 + -9y + -3y2 + y3 = 0

Solving
27 + -9y + -3y2 + y3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
y = {0}

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